Chapter 6
The Moving Target Laws
"A
ship in port is safe, but that's not what ships are built for."
Grace
Hopper. (The computer term "bug" is also due to Grace Hopper)
Introduction to The Moving Target Laws
When I
talk about the "path of light," I am really talking about the Moving
Target
Laws.
It is critical for the reader to have an exact understanding of what the
Moving
Target Laws are in order to understand any of my experiments or the
Lunar
Laser Ranging experiments. This chapter will provide that understanding.
Consider
an archer who is a perfect shot and always hits the exact center of the
bulls-eye.
Now consider the archer and his target as a three-dimensional
coordinate
system. The two-dimensional target is on the X-Z plane. The path of
the
arrow is the Y axis. The X axis, Y axis and Z axis all meet at a point that is
also
the center of the bulls-eye of the target. Suppose further that the archer is
100
feet from the target.
See
graphics on next page.
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Now
suppose the archer aims at the target and that I am holding the target.
Suppose
that after the arrow leaves the bow, but before the arrow gets to
the
target,
two things happen: 1) I move the target one-foot straight up and 2) the
archer
throws the bow into a trashcan. The arrow will obviously land one foot
below the
(center of the) bulls-eye. This example, as with all examples, assumes
the
archer is a perfect shot, there is no arch on the arrow, the experiment is done
in a
vacuum, etc.
The
key to understanding the Moving Target Laws (MTLs) is to understand the
slice
of time between:
1) The
instant after the arrow leaves the bow and
2) The
instant before the arrow hits the target.
This
slice of time is the time the arrow is "in the air." "In
the air" means the
arrow
is no longer attached to the bow, and has not yet hit the target. While the
arrow
is "in the air," what happens to the archer and the bow is irrelevant
because
the arrow is no longer attached to the bow. As I implied above, while
the
arrow is in the air, the archer can throw the bow into the trashcan and this
act
will
have absolutely no affect on where the arrow hits the target. While the arrow
is
"in the air" the bow and arrow are totally independent of each other.
But
the same cannot be said about the target. While the arrow is in the air, it is
headed
towards the target. Thus any motion of the target, while the arrow is in
the
air, has a direct affect on where the arrow hits the target! This is why
they
are
called the "moving target" laws.
The
MTLs basically study the motion of the target during the slice of
time the
arrow
is in the air. In the example just given, after the arrow leaves
the bow, but
before
it gets to the target, the target is moved one-foot
straight up. Thus the
moving
of the target has a direct affect on where the arrow hits the target.
More Examples of the MTL
If I
were to move the target exactly one foot down while the arrow is in the air,
the
arrow
would land one foot above the (center of the) bulls-eye. If I move the
target
exactly one foot to my right (while the arrow is in the air),
which is to the
archer's
left, the arrow would miss the target by exactly one foot to my left. I am
behind
the target so the arrow would hit to the left of the bulls-eye from my
perspective.
But from the archer's perspective, the arrow would land to the
archer's
right (i.e. the archer would see the arrow land one foot to the right of the
bulls-eye).
And so on.
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Now
let us do thousands of these exercises. Suppose that after the arrow leaves
the
bow, that I am allowed to move the target exactly one foot on the
twodimensional
X-Z
plane, and that I can move the target in any of the 360 degrees
of the
plane. If we were to do this exercise thousands of times there would be up
to 360
holes that would form a perfect circle (i.e. the holes would all be on the
outside
edge or perimeter of the circle), with the center of the bulls-eye being the
center
of the circle. No holes would be inside or outside of the perimeter of
holes.
Now
let us construct an imaginary three-dimensional sphere with the center of
the
sphere being the center of the bulls-eye. The imaginary sphere has a radius
of
exactly one-foot. Now let us change the rules. I can move the target exactly
one
foot while the arrow is in the air, but I can move it in any direction in
threedimensions, as long as the center of the target ends up being on the
surface of
the
imaginary three-dimensional sphere when the arrow arrives.
In
other words, the center of the bulls-eye will always be on the surface of the
imaginary
sphere by the time the arrow arrives. Since the sphere is in three
dimensions,
but the target is only in two dimensions, I can move the target such
that
the arrow can hit any point within a one-foot radius of the center of the
bullseye.
As an
example, if I were to move the target along the Y-Axis, directly towards the
archer
or directly away from the archer, ignoring the arch of the arrow, the arrow
would
hit the center of the bulls-eye even though I moved the target one-foot. If I
were
to move the target slightly off of the Y-Axis, the arrow would just miss the
bulls-eye.
Now
suppose this three-dimensional experiment were done thousands of times
and I
moved the target randomly. In this case an imaginary circle of one-foot
radius
on the target, with the bulls-eye at the center, would have many arrow
holes
in it or on its perimeter. In other words, instead of just being on the
perimeter
of the circle, the holes would also occupy the inside of the circle.
Now
suppose we studied one specific hole in the target. Let us suppose that I
moved
the target one-foot at such an angle on the sphere that the arrow missed
the
center of the target by exactly 5 inches. Studying the angle that the hole is
from
the bulls-eye, the angle that I moved the target could easily be determined.
However,
since the target itself has only two-dimensions, it could not be
determined
whether I moved the target generally towards the archer or generally
away
from the archer (on the Y-Axis). Thus the solution to exactly how I moved
the
target in three-dimensions could only be reduced to two possibilities.
If an
observer were standing on the side of the target, she could note whether the
target
were moved forward or backwards because she would see the Y-Z axis.
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Thus
she could determine the Y-Axis movement and narrow the possibilities
down
to one.
More Complex Archer Examples
Now
let us suppose that I am standing on a flatbed car on a moving train. Again,
I am
holding the target. We will assume the archer is standing on a train station
platform.
The flatbed car is moving with the train (along with the target), but the
archer
is not moving. Let the distance between the archer and the target be 100
feet.
Let us
assume that the train is moving at such a speed that in the time it takes
the arrow
to travel to the target the train moves exactly 1 foot (the train is in
constant
motion). Now suppose the archer lets go of the arrow at the exact
instant
that the bulls-eye passes him. Now suppose that I do not move the
target,
but hold it still. The arrow will again miss the target by 1 foot. If the train
is
moving left to right (per the archer), the arrow will land to the left of the
bullseye
by 1
foot.
If
additionally I had moved the target one-foot in the direction the train is
traveling,
the arrow would miss the bulls-eye by 2 feet. It would miss the bullseye
by 1
foot because of my moving the target and another foot because of the
moving
train.
However,
if I moved the target in the opposite direction the train is traveling, the
arrow
would hit the center of the bulls-eye. The 1-foot miss caused by the
motion
of the train would be offset by the 1-foot miss caused by my moving the
target.
In
these cases the platform that the target is standing on (i.e. the
flatbed car) is
in
motion, thus the motion of the platform has a direct affect on the motion of
the
target
while the arrow is in the air. The MTLs apply both to my movement of the
target,
and to the platform's movement of the target. Anything that moves the
target
while the arrow is in the air is significant to where the arrow hits the
target.
In the
experiments that are discussed in future chapters, the platform will be the
earth,
the archer will be a laser, and the arrow will be a laser beam.
One of
the hardest things for people to grasp about the moving target laws is that
once
the arrow or laser beam is "in the air," the motion of the archer or
the
motion
of the laser is irrelevant. People constantly wonder why the motion of the
archer
or laser is irrelevant. Many examples will be given to make this distinction
clear.
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The
MTLs will be mentioned many times in this book. They are not only the
basis
of aberration of starlight, but are also directly involved with all of my
experiments
and any experiment that involves the path of light.
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